Answer:
t = V0 sin theta / g time to get max height
h = Voy t - 1/2 g t^2 = Vo^2 sin^2 theta / 2 g max height
R = V0^2 sin 2 theta / g range formula
h = 3 R given
Vo^2 sin^2 theta / 2 g = 3 * V0^2 sin 2 theta / g
sin^2 theta = 6 * sin 2 theta = 12 * sin theta cos theta
tan theta = 12
theta = 85.2 deg
Can check:
Vx = 8.37
Vy = 99.6 assuming V0 =100
t = 99.6 / 9.8 = 10.2 sec to reach max height
Sx (total range) = 2 * 10.2 * 8.37 = 170 m
Sy = 1/2 * 9.8 * (10.2)^2 = 510 m
Height = 3 * range