Question

Ickets to the zoo cost $15 for adults and $10 for children. The school has a budget of $300 for the field

trip. An equation representing the budget for the trip is 15x+10y = 300.
a. With a budget of $300, determine if 21 students and 6 adults can go to the zoo. Explain how you
know.
b. If there are four adults who need tickets, what is the maximum number of students who can go to
the zoo while staying within the school budget? Show or explain your reasoning.
c. Solve the equation15x+10y = 300 for y.

Answer 1

Answers: lol sorry very long answer

part a answer: Yes, because if we substitute the variables, the equation will be 15(6) + 10(21) = 300. Simplifying this will be 90 + 210 = 300. And since 90 + 210 does equal 300, 21 students and 6 adults can go to the zoo

part b answer: 24 students. Using the equation 15x + 10y = 300, we can find out the maximum number of students who can go to the zoo. First we can substitute x for 4 because that's how many adults who need the tickets. The equation will now be 15(4) + 10y = 300. Simplifying this will be 60 + 10y = 300. Now we can subtract 60 on both sides to isolate the y term. The equation will be 10y = 240. Divide each side by 10 to find out what y is and we get y = 24. So if 4 adults go the zoo, up to 24 students can go.

part c answer: y = 30 - 1.5x. To solve 15x + 10y =300, we first need to move 15x to one side of the equation. To do this we will subtract it on both sides. The equation is now 10y = 300 -15x. Then you will divide 10 on both sides to find out what y is. y = 30 - 1.5x.