Question

X=-3

f(x)= -2
f’(x)=2
g(x)=3
g’(x)=-1

h(x) = g(x)/2f(x)
Find h'(-3)

Answer 1

Answer:
`-1`

Explanation:

Using the quotient rule,

`h'(x)=(2f(x)g'(x)-2g(x)f'(x))/((2f(x))^2)\\\\h'(3)=(2f(3)g'(3)-2g(3)f'(3))/((2f(3))^2)\\\\=(2(-2)(-1)-2(3)(2))/(2(-2)^2)\\\\=-1`