Question

what is the momentum of an 7.2- kgkg bowling ball rolling at 3.0 m/sm/s ? express your answer to two significant figures and include the appropriate units.

Answer 1

Answer: 20.16kg.m\s

Explanation: Here is given that M= 7.2 Kg, and v= 2.8 m/s So, momentum ,P=M. v = (7.2*2.8) = 20.16 Kg. m/s, which is a number having four significant digits. but we have to provide the answer in two significant digits. Therefore, to convert