Answer:
Kinetic Energy is 1.59x10^7 Newtons
Potential Energy cannot be determined since no height is given. An example calculation is provided that assumes 3000 meters.
Step-by-step explanation:
Kinetic energy is directly proportional to the mass of the object and to the square of its velocity:
K.E. = 1/2 m v2.
If the mass is in kilograms and the velocity in meters per second, the kinetic energy has units of kilograms-meters per second squared, which is 1 Newton. (A newton is defined as 1 kg⋅m/s2. 1 Joule is defined as 1 N*m, or 1 kg⋅m2/s2
Data: 8500 kg airplane
220 km/h flight speed
We'll convert the speed from km/h to m/sec.
(220 km/h)*(1 h/3600 sec)*(1000m/1km) = 61.1 m/s
Kinetic Energy:
K.E. = 1/2 m v2
K.E. = 1/2 (8500 kg)*(61.1 m/s)^2
K.E. = 1/2 (8500 kg)*(3733 m^2/s^2)
K.E. = 1.59x10^7 kg*m^2/s^2
K.E. = 1.59x10^7 Newtons
Potential Energy
The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
P.E. = mgh
P.E. = (8500kg)*(9.8 m/s^2)*(h)
I don't see a height given for the plane, so we can't calculate a potential energy. If it were at 3000 meters (1.86 miles), the calculation would be:
P.E. = (8500kg)*(9.8 m/s^2)*(3000 m)
P.E. = (2.5x10^8 kg*m/s^2) or 2.5x10^8 Newtons