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find the values for c and d that make the function differentiable:f(x) = 5x^2 + c if x = or < than 3dx^2 - 3 if x > 3

User Daemontus
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1 Answer

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Answer:

c = -3; d = 5

Explanation:

The function is differentiable if it is continuous and the derivative is continuous.

This function will be continuous if the limit as x approaches 3 from either side is the same. From the left, the limit is ...

5(3^2) +c = 45 +c

From the right, the limit is ...

d(3^2) -3 = 9d -3

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The derivative will be continuous if the limit as x approaches 3 from either side is the same. From the left, the limit is ...

f'(x) = 10x

= 10(3) = 30

From the right, the limit is ...

f'(x) = 2dx

= 2d(3) = 6d

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This gives us a pair of simultaneous equations in 'c' and 'd':

45 +c = 9d -3

6d = 30

The latter tells us d = 5. Then the former tells us ...

45 +c = 9(5) -3 ⇒ c = -3

The function is differentiable if c = -3 and d = 5.

_____

Additional comment

With these values, the function becomes ...


f(x)=\begin{cases}5x^2-3&amp;\text{if }x\le 3\\5x^2-3&amp;\text{if }x>3\end{cases}

User Egor Rogov
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