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4 votes
Please show me how to factorize this

5x {}^(3) - 9x {}^(2) - 17x - 3


User Kristena
by
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1 Answer

5 votes

Answer:

(x - 3) (5x + 1)(x + 1).

Explanation:

5x^3 - 9x^2 - 17x - 3

As the first coefficient is 5 and the last -3, so product is -15, we could try if (x-3) is a factor:

By the Factor Theorem, if x-3 is a factor then f(3) = 0.

f(3) = 5(3)^3 - 9(3)^2 - 17(3) - 3

= 135 - 81 - 51 - 3 = 0

So, x - 3 is a factor.

Now divide:

x - 3)5x^3 - 9x^2 - 17x - 3(5x^2 + 6x + 1 <------- Quotient

5x^3 - 15x^2

6x^2 - 17x

6x^2 - 18x

x - 3

x - 3

.......

Factoring 5x^2 + 6x + 1:

= (5x + 1)(x + 1)

So, the answer is:

(x - 3) (5x + 1)(x + 1).

User Psms
by
4.8k points