Given the function:

Let's determine if the function has a minimum or maximum.
The minimum and maximum of a function are the smallest and largest value of a function in a given range or domain
The given function has a minimum.
Apply the general equation of a quadratic function:

To find the minimum value, apply the formula:

Where:
b = -12
a = 2
Thus, we have:

To find the function's minimum value, find f(3).
Substitute 3 for x in the function and evaluate:

Therefore, the function's minimum value is 1
Therefore, the functions minimum value occurs at:
x = 3
ANSWER:
• The function has a minimum
• Minimum value: 1
• The minimum occurs at: x = 3