Question

What is the mass of 5.36 mol of ammonia
vapor (NH3)?
Answer in units of g.

Answer 1

91.12 gram

Step-by-step explanation:

Number of moles of Ammonia = 5.36

Molecular Mass of Ammonia = 14 + 3 × 1 = 17 gram/mol

Mass = Number of moles × Molecular mass

Mass = 5.36 mol × 17 gram/mol = 91.12 gram