Question

I wonder what I’m doing wrong ?

P^2-10p+16=1+6p


Answer is (15,1)
But I can’t seem to figure it out.

Answer 1

Steps to Solve:

1. Collect like terms

2. Factor quadratic

3. solve for p

Factoring a Quadratic where a = 1

1. find two numbers that are the product of ac and the sum of b

2. set up the two linear terms with the variable associated with a

2. insert the values found in step 1 into parentheses

1. collect like terms

`p^2-10p-6p+15-1=0`

`p^2-16p+15 = 0`

2. Factor quadratic

• ac = 15 and b =-16, two numbers that multply to ac and are the sum of b are -15 and 1

`(p-15)(p-1)=0`

• 2 solutions can be found

`p-15=0` OR
`p-1=0`

`p= 15`
`p=1`