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X^2-8x+9
find x using the quadratic formula

User Hanyu Guo
by
8.2k points

1 Answer

4 votes

Answer:


x = 4 \pm \sqrt7

Explanation:

Hello!

Standard form of a Quadratic:
ax^2 + bx + c= 0

Given the Equation:
x^2 -8x+9=0

  • a = 1
  • b = -8
  • c = 9

Quadratic Formula:
x = (-b \pm √(b^2 - 4ac))/(2a)\\

Solve by substituting the values into the Quadratic Formula.

Solve for x


  • x = (-b \pm √(b^2 - 4ac))/(2a)\\

  • x = (-(-8) \pm √((-8)^2 - 4(1)(9)))/(2(1))\\

  • x = (8 \pm √(64 - 36))/(2)\\

  • x = (8 \pm √(28))/(2)\\

  • x = (8 \pm 2√(7))/(2)\\

  • x = 4 \pm \sqrt7

The solution to the quadratic is
x = 4 \pm \sqrt7.

User Frank Odoom
by
7.7k points

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