Question

Find an equation for the line that passes through the points (-2,-6) and (6,-4).

Answer 1

`(y+6)=(2)/(8) (x+2)`

Explanation:

First, find the slope

`m=(y2-y1)/(x2-x1)`

-4+6=2

6+2=8

m=2/8

With the slop, you have everything you need to stick one of your points in point-slope form. I chose (-2,-6)

`(y-y1)=m(x-x1)\\(y+6)=(2)/(8) (x+2)`

Really, that's all you need as it is not an equation of a line. Not the most useful form, but works as an answer.