Question

Write an equation in slope- intercept form for the line that passes through (-8,-7) and is perpendicular to the graph y= -x-8

Answer 1

The equation of the line is y = x + 1.

Step-by-step explanation:

To find the equation of a line perpendicular to the given line, we need to determine the slope of the perpendicular line. The given line has a slope of -1. The perpendicular line will have a slope that is the negative reciprocal of -1, which is 1.

Using the point-slope form of a line, we can plug in the values of the given point (-8,-7) and the slope (1) to find the equation. The equation in slope-intercept form is y = 1x + b, where b is the y-intercept.

Using the coordinates of the point (-8,-7), we can substitute these values into the equation and solve for b. -7 = (1)(-8) + b. Solving this equation, we get b = 1.

Therefore, the equation of the line that is perpendicular to y = -x-8 and passes through (-8,-7) is y = x + 1.

Answer 2

Answer: y=-1/8x

Step-by-step explanation:

Choose a point that the perpendicular line will pass through.

(0,0)

Use the slope-intercept form to find the slope.

m=8

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

perpendicular

m= −1/8

Find the equation of the perpendicular line using the point-slope formula.

y+0=−1/8⋅(x+0)

Write in

y=mx+b

form.

y=−1/8x

Hope this helps