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A 0.300 kg mass is attached to 26.6N/m spring.It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m fro equilibrium?​
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A 0.300 kg mass is attached to 26.6N/m spring.It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m fro

equilibrium?​

A 0.300 kg mass is attached to 26.6N/m spring.It is pulled 0.120 m and released. How-example-1
User JohnnBlade
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Answer:

Step-by-step explanation:

The elastic potential energy equation is EPE = (1/2) k x2, where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)2 = 0.0479 Joules.

User Imma
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