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NO LINKS!! Please help me with this probability question. 4a​

NO LINKS!! Please help me with this probability question. 4a​-example-1
User Gacrux
by
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1 Answer

1 vote

Answer: 11.5% (choice B)

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Step-by-step explanation:

mu = 500 = mean

sigma = 100 = standard deviation

We'll need the z score for x = 620

z = (x - mu)/sigma

z = (620-500)/100

z = 1.20

The task of finding P(x > 620) is equivalent to P(z > 1.20)

Use a Z table or a Z calculator to find that

P(Z < 1.20) = 0.88493

which leads to

P(Z > 1.20) = 1 - P(Z < 1.20)

P(Z > 1.20) = 1 - 0.88493

P(Z > 1.20) = 0.11507

This converts to 11.507% and rounds to 11.5%

About 11.5% of the students score higher than a 620 on the SAT.

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Another approach:

Open your favorite spreadsheet program. The command we'll be using is called NORMDIST. The template is this

NORMDIST(x, mu, sigma, 1)

  • x = 620 = critical value
  • mu = 500 = mean
  • sigma = 100 = standard deviation
  • The 1 at the end tells the spreadsheet to use a CDF instead of PDF. Use 0 if you want a PDF value.

If you were to type in
\text{=NORMDIST(620,500,100,1)} then you'll get the area under the normal distribution to the left of x = 620

This means
\text{=1-NORMDIST(620,500,100,1)} will get us the area to the right of 620. The result of that calculation is approximately 0.11507 which leads to the same answer of 11.5% as found earlier.

When using a spreadsheet, don't forget about the equal sign up front. Otherwise, the spreadsheet will treat the input as text and won't evaluate the command.

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Another option is to use a TI83 or TI84 calculator.

Press the button labeled "2nd" in the top left corner. Then press the VARS key. Scroll down to "normalcdf"

The template is

normalcdf(L, U, mu, sigma)

  • L = lower boundary
  • U = upper boundary
  • mu = mean
  • sigma = standard deviation

The mu and sigma values aren't anything new here. But the L and U are. In this case L = 620 is the lower boundary and technically there isn't an upper boundary since it's infinity. Unfortunately the calculator wants a number here, so we just pick something very large. You could go for U = 99999 as the stand in for "infinity". The key is to make sure it's more than 3 standard deviations away from the mean.

So if you were to type in
\text{normalcdf(620,99999,500,100)} then the calculator will display roughly 0.11507, which is in line with the other answers mentioned earlier.

As you can see, there are many options to pick from. Searching out "normal distribution calculator" or "z calculator" will yield many free options. Feel free to pick your favorite.

User MortalViews
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