Question

Please only answer if you know the answer thank you.

Answer 1

x = -5

y = 5

Explanation:

You could write the equation in the point slope form of a line

y -
`y_(1)` = m( x -
`x_(1)`)

Use the slope they gave us 2/3. Use the point they gave us for
`x_(1)` ( -2 ) and
`y_(1)` ( 5)

y -5 = 2/3(x - -2)

y - 5 = 2/3(x + 2) Plug in 3 for y to solve for x

3-5 = 2/3(x + 2)

-2 = 2/3x + 4/3 subtract 4/3 from both sides of the equation

-2 - 4/3 = 2/3x

`(-6)/(3)` -
`(4)/(3)` = 2/3x

`(-10)/(3)` = 2/3 x Multiply both sides by
`(3)/(2)`

(
`(3)/(2)`)
`(-10)/(3)` = (
`(3)/(2)`)(
`(2)/(3)`) x

-5 = x

substitute in -2 for x to solve for y

y - 5 = 2/3(x + 2)

y - 5 = 2/3(-2+2)

y - 5 = 2/3(0)

y - 5 = 0 Add 5 to both sides

y = 5

Answer 2

x = - 5;

y = 5;

Step-by-step explanation:

Identify the equation.

y = ( 2 / 3 )x + c;

Substitute a point.

5 = ( 2 / 3 )( - 2 ) + c;

5 = ( - 4 / 3 ) + c;

5 - ( - 4 / 3 ) = c;

5 + ( 4 / 3 ) = c;

19 / 3 = c;

y = ( 2 / 3 )x + ( 19 / 3 );

Substitute point A.

3 = ( 2 / 3 )x + ( 19 / 3 );

3 - ( 19 / 3 ) = ( 2 / 3 )x;

( 9 / 3 ) - ( 19 / 3 ) = ( 2 / 3 )x;

- ( 10 / 3 ) = ( 2 / 3 )x;

- ( 10 / 3 )( 3 / 2 ) = x;

( - 30 / 6 ) = x;

- 5 = x;

x = - 5;

Substitute point B. Use common sense and notice that point B is actually the same as the first point.

y = 5;