If 79.5 mol of an ideal gas is at 8.91 atm at 47.20 °C, what is the volume of the gas?

Leigero asked Jul 24, 2022

247,820 views

2 votes

Leigero asked Jul 24, 2022

3.3k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

23 votes

Answer:

235L

Step-by-step explanation:

PV =nRT

V = nRT/P

47.20 °C is 320.35K

V = (79.5 mol)(0.0821 atm•L/mol•K)(320.35K)/8.91atm

V = 234.6698577L

Round to 3 sig figs: 235L

3.2k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers