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Write the equation of a line in slope intercept form that passes through (-15, 20) and is parallel to x - 5y = 5

1 Answer

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First step is to write the equation in slope-intercept form


x - 5y = 5\\-5y = -x+5 To make simplification easier, multiply negative to both sides


5y = x-5\\ Now, you must divide 5 to both sides to isolate the variable


y = (x)/(5) - 1 To tell the slope more easily, turn
(x)/(5) into
(1)/(5) x

To rewrite the equation:
y = (1)/(5) x - 1

Now, you are able to see the slope(m) being
(1)/(5)

Next, you use the formula y=mx+b to solve for b (replace your newly found slope and points "x" and "y"


20 = ((1)/(5) *-15) + b\\20 = -3 + b\\b -3 = 20\\b = 23

Final Answer:
y = (1)/(5) + 23

Hope this helps :)

User Tschomacker
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