Question

Find the equation of the circle (2, 3) and radius 4​

Answer 1

Answer:
`(\text{x}-2)^2+(\text{y}-3)^2 = 16`

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Step-by-step explanation:

The general circle template is

`(\text{x}-\text{h})^2+(\text{y}-\text{k})^2 = \text{r}^2`

(h,k) = center

r = radius

Assuming the center is (2,3) then we have h = 2 and k = 3. We also have a radius of r = 4.

`(\text{x}-\text{h})^2+(\text{y}-\text{k})^2 = \text{r}^2\\\\(\text{x}-2)^2+(\text{y}-3)^2 = 4^2\\\\(\text{x}-2)^2+(\text{y}-3)^2 = 16\\\\`