Question

Make k the subject
2A= πK^2 +3t

Answer 1

k = ±
`\sqrt{(2A-3t\p)/(\pi ) }`

Explanation:

2A = πk² + 3t ( subtract 3t from both sides )

2A - 3t = πk² ( isolate k² by dividing both sides by π )

`(2A-3t)/(\pi )` = k² ( take square root of both sides )

±
`\sqrt{(2A-3t)/(\pi ) }` = k