Question

The vertices of △ABC are A(2, −3), B(−3, −5), and C(4, 1). If (x,y)--> (x-4, y-1), give the vertices of △A′B′C′.

Answer 1

A' = (-2, -4)

B' = (-7, -6)

C' = (0, 0)

Explanation:

Vertices of triangle ABC:

• A = (2, -3)
• B = (-3, -5)
• C = (4, 1)

Given mapping rule:

(x, y) → (x - 4, y - 1)

This notation tells you that the x-coordinate is translated 4 units to the left, and the y-coordinate is translated 1 unit down.

Substitute the coordinates of each point into the mapping rule to find the vertices of triangle A'B'C':

⇒ A' = (2 - 4, -3 - 1) = (-2, -4)

⇒ B' = (-3 - 4, -5 - 1) = (-7, -6)

⇒ C' = (4 - 4, 1 - 1) = (0, 0)