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Write the equation of the line that passes through the points (3,1)(3,1) and (-7,-1)(−7,−1). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.

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Answer:


\textsf{Point-slope form}: \quad y-1=(1)/(5)(x-3)

Explanation:

Define the given points:

  • (x₁, y₁) = (3, 1)
  • (x₂, y₂) = (-7, -1)

Substitute the defined points into the slope formula to find the slope of the line:


\implies \textsf{Slope $(m)$}=(y_2-y_1)/(x_2-x_1)=(-1-1)/(-7-3)-(-2)/(-10)=(1)/(5)

Substitute the found slope and one of the points into the point-slope formula:


\implies y-y_1=m(x-x_1)


\implies y-1=(1)/(5)(x-3)

Simplify to slope-intercept form, if necessary:


\implies y-1=(1)/(5)x-(3)/(5)


\implies y=(1)/(5)x+(2)/(5)

User Mattygabe
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