Question

What is the slope of a line perpendicular to the line whose equation is 3x+y=8

Answer 1

slope =
`(1)/(3)`

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

3x + y = 8 ( subtract 3x from both sides )

y = - 3x + 8 ← in slope- intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-3)` =
`(1)/(3)`