68.3k views
3 votes
a herd of 55 cows eat 3250 pounds of silage daily . if the herd size increases to 80 cows how much more will be needed daily ?

1 Answer

4 votes

Answer:

1,475 lbs.

Step-by-step explanation:

Divide the current amount of silage eaten by the current amount of cows to find how much food one cow eats:

3250 ÷ 55 = 59

Then, subtract the current herd size from the new herd size to find how many new cows will be added to the herd:

80 - 55 = 25

Now, multiply the amount of new cows by the amount of silage eaten per cow:

25 * 59 = 1,475

There will need to be 1,475 more pounds of silage daily.

User Georges Legros
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.