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1 vote
2. Kieran, Jermaine and Chris play football. Kieran scored 8 more goals than Chris Jermaine scored 5 more goals than Kieran. Altogether they have scored 72 goals. How many goals did they each score?​

User MacHala
by
4.5k points

2 Answers

6 votes

Answer:

Explanation:

k = x+8

c= x+5

j= x+5

3x+18=72

x = 18

Chris = 23

Kieran = 26

Jermaine = 23

User Gunderson
by
4.1k points
3 votes

Answer:

Chris = 17 goals

Kieran = 25 goals, and

Jermaine = 30 goals

Explanation:

Let K, J, and C stand for the goals scored by Kieran, Jermaine, and Chris, respectively.

We learn that:

K = C + 8 [Kieran scored 8 more goals than Chris]

J = K + 5 [Jermaine scored 5 more goals than Kieran]

K + J + C = 72 [Altogether they have scored 72 goals]

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We have 3 equations and 3 unknowns. Therefore, we should be able to find a solution by rearranging and substituting.

Let's start with K + J + C = 72 and find ways to eliminate two of the three variables.

We can substitute for K since K = C + 8

K + J + C = 72

(C+8) + J + C = 72

Rearrange:

2C+8 + J = 72

We can also substitute for J since J = K + 5

2C+8 + J = 72

2C+8 + (K + 5) = 72

Again, we can substitute for K since (K = C + 8)

2C+8 + (C+8) + 5 = 72

2C+8 + (C+8) + 5 = 72

3C +21 = 72

3C = 51

C = 17

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Since C = 17, we can find K with K = C + 8

K = C + 8

K = 17 + 8

K = 25

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Since K = 25, we can find J with J = K + 5

J = K + 5

J = 25 + 5

J = 30

===

We find:

C (Chris) = 17 goals

K (Kieran) = 25 goals, and

J (Jermaine) = 30 goals

17 + 25 + 30 = 62 total goals.

User Gordon Williams
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4.2k points