Answer:
9 terms
Explanation:
The sequence given is a geometric sequence
In a geometric sequence, the nth term of the sequence can be found by the formula
![a_n = a_1r^(n-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wnba4xdki4hikcdwumnil5dkx2rwj4wkrt.png)
![\text{where }\\\\ a_n = \text {nth term}\\\\\text{$a_1 = $ first term}\\\\\text{$r = $ common ratio}](https://img.qammunity.org/2023/formulas/mathematics/high-school/425o6t098np4v0anz669hm8tf0tumsb0ce.png)
In the given sequence,
a₁ = 1
r = -4
aₙ = 65536
So we get the relation:
65536 = 1· (-4)ⁿ⁻¹
65536 = (-4)ⁿ⁻¹
It is clear that n-1 has to be even so that the power of 4 is positive.
Substituting x = n -1 where x is even gives us
4ˣ = 65536
If we take logarithms to the base 4 on both sides we get
=> x =
![\log_465536 = 8\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/zmth9pmkjfkvyjptzmufrfe9nepixzxkl6.png)
Since x = n - 1 and x = 8, n = 9
So the 9th term in the series is 65536