Final answer:
The amount of the third check deposited by Jim Russo was $294.00. The total deposit before receiving cash was calculated and then the amounts of the first two checks were subtracted to find the amount of the third check.
Step-by-step explanation:
The student asked what the amount of the third check deposited by Jim Russo was, given his total deposit and the amounts of the other checks and cash received. We can calculate this by setting up an algebraic equation based on the information provided.
- First check: $536.75
- Second check: $347.50
- Total deposit after receiving cash: $1,253.25
- Cash received: $75.00
Let's denote the amount of the third check as x. The total deposit before receiving cash would then be $1,253.25 minus $75.00, which is $1,178.25. The total deposit is the sum of all three checks, so we set up the following equation:
Total deposit before cash = First check + Second check + Third check
$1,178.25 = $536.75 + $347.50 + x
To find the value of x, we add the amounts of the first two checks together and subtract that sum from the total deposit before receiving cash:
$1,178.25 - ($536.75 + $347.50) = x
$1,178.25 - $884.25 = x
x = $294.00
Therefore, the amount of the third check deposited was $294.00.