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Solve the quadratic equation
3x^(2) +x-5=0
give your answers to 2 decimal places

1 Answer

3 votes

Answer:

-1.47, 1.14 to 2 decimal places.

Explanation:

3x^2 + x - 5 = 0

3(x^2 + 1/3x) - 5 = 0

Completing the square on the expression in the parentheses:

3[(x + 1/6)^2 - 1/36) - 5 = 0

3(x + 1/6)^2 - 1/12 - 5 = 0

(x + 1/6)^2 = 61/12 / 3

(x + 1/6)^2 = 61/36

(x + 1/6) = +/-√61 / 6

x = -1/6 +/- √61 / 6

x = 1.135, -1.468

User Ahmad Mushtaq
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