Answer:
25.
Explanation:
At time 2, x(t) = 2(2)^2 + 2 = 10
At time 10, x(t) = 2(10)^2 + 10 = 210.
Average speed for this interval
distance / time
= (210 - 10) / (10 - 2)
= 200/8
= 25.
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