Question

Select the correct answer.

Which equation represents the hyperbola (v-2)² – (-2)² = 1 in general form?
1
(y-2)²-(x - 2)² - 36 = 0
2-x²-4y + 4x - 36 = 0
9y2-4x²-36y-16x - 16 = 0
OD. 9y2-4x² - 36y + 16x-16 = 0

Answer 1

OD. 9y2-4x²-36y+16x-16=0

Explanation:

1)

(y-2) (x-2)²

------ - ------- = 1

4 9

2)

9 (y-2)²-4 (x-2)²=36

9y²-36y+36-4x²+16x-16-36=0

removing the fractions:

9y²-4x²-36y+16x-16=0

hope this helps :)