Question

The distances of a port from 20 differ- ent locations form an AP. If the farthest distance is 300 km, and the nearest distance is 30 km, what is the distance between any two successive locations? ?​

Answer 1

Required difference = 270/19 km

Explanation:

If we consider the AP of distances to be

a, a + r, a + 2r, ..., a + 19r,

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

Given that,

a + 19r = 300 .....(1)

a = 30 ..... (2)

Using (2), from (1), we get

30 + 19r = 300

or, 19r = 300 - 30

or, 19r = 270

or, r = 270/19

Therefore the distance between any two successive location is 270/19 km.