Question

Find the 63rd term of the following arithmetic sequence.
17, 21, 25, 29, ...

Answer 1

265

Explanation:

the nth term of an arithmetic progression is given by

[a+(n-1)d]

where "a" is the first term, "d" is the common difference and "n" is the term you're looking for

from the question, a= 17

d=4

n=63

substituting, [17+(63-1)4]=[17+248]=265