Answer:
There are 2 1/5 bars of chocolate left over.
Explanation:
In this word problem you’ll subtract the two fractions given.
1. In order to subtract mixed fractions you must turn them into improper fractions, or a fraction with a numerator that is greater than the denominator. To do this you must multiply the whole number by the denominator then add by the numerator.
30 7/10 - 28 1/2 = 307/10 - 57/2
30 x 10 + 2 = 307
28 x 2 + 1 = 57
2. Next, we must find the least common denominator of both fractions. To find this you can list the multiples of the two denominators, 10 and 2.
Multiples of 10: Multiples of 2:
1 x 10 = 10 1 x 2 = 2
2 x 10 = 20 2 x 2 = 4
3 x 10 = 30 3 x 2 = 6
4 x 10 = 40 4 x 2 = 8
5 x 10 = 50 5 x 2 = 10
If we compare the two, we can see that both 10 and 2 have a common multiple of 10.
3. Rewrite the problem using the common denominators, make sure to multiply the numerator.
307/10 - 285/10
4. Now that the denominators are the same, subtract the numerators.
307/10 - 285/10 = 22/10 or 2 2/10
5. Simplify if possible. To do this you must find the greatest common factor of the two numbers.
Factors of 10; 1, 2, 5, 10
Factors of 2; 1, 2
If we compare the two we can see they have 1 and 2 listed as a common factor. But, we need the greatest common factor, which is 2.
6. Simplify, divide both the numerator and denominator by 2.
2 2/10 = 2 1/5