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EASY) write and equation for x then solve for x

EASY) write and equation for x then solve for x-example-1
User Oleg  Rogov
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Answer:


\large\boxed{\tt x = 23^(\circ)}

Explanation:


\textsf{We are given 2 \underline{Linear Pairs}. We are asked to form an equation, and to solve for x.}


\large\underline{\textsf{What are Linear Pairs?}}


\textsf{Linear Pairs are 2 Adjacent Angles that form a 180}^(\circ) \ \textsf{angle, or add up to 180}^(\circ).


\textsf{For our problem, these 2 angles given to us are Linear Pairs, which equal 180}^(\circ)


\textsf{when added together. Let's create an equation to find x.}


\large\boxed{\tt 180^(\circ)=93^(\circ) + (3x+18)^(\circ)}


\textsf{Now, let's solve for x by using the \underline{Properties of Equality}.}


\large\underline{\textsf{What are the Properties of Equality?}}


\textsf{The Properties of Equality are Properties that allow us to manipulate equations.}


\textsf{There are 9 properties of equality that we can use, each allowing us to simplify}


\textsf{one side of an equation. These properties are mainly used to find missing variables.}


\textsf{Let's solve for x by using the Properties of Equality.}


\large\underline{\textsf{Solving for x;}}


\tt 180^(\circ) = 93^(\circ) + 3x^(\circ)+18^(\circ).


\textsf{Let's first Combine Like Terms.}


\tt 180^(\circ) = \boxed{\tt 93^(\circ)} + 3x^(\circ)+\boxed{\tt 18^(\circ)}


\tt 180^(\circ) = 111^(\circ) + 3x^(\circ)


\textsf{Now, let's use the Subtraction Property of Equality which states that if 2 same}


\textsf{numbers are subtracted from both sides of the equation, then both expressions}


\textsf{still equal each other. Let's subtract 111 from both sides of the equation.}


\tt 180^(\circ) - 111^(\circ) = 111^(\circ) - 111^(\circ) + 3x^(\circ)


\tt 69^(\circ) = 3x^(\circ)


\textsf{Let's use the Division Property of Equality, which is similar to subtraction but it's}


\textsf{for division. Divide each side of the equation by 3.}


\tt (69^(\circ))/(3) = (3x^(\circ))/(3)


\large\boxed{\tt x = 23^(\circ)}

User Quid
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