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Which equation is perpendicular to
5x-10y=6 and passes through (2,1)

User Ronyis
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1 Answer

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Answer: Answer: y=5−2x

Explanation:

The equation of the line in the slope-intercept form is y=x2−35.

The slope of the perpendicular line is negative inverse: m=−2.

So, the equation of the perpendicular line is y=−2x+a.

To find a, we use the fact that the line should pass through the given point: 1=(−2)⋅(2)+a.

Thus, a=5.

Therefore, the equation of the line is y=5−2x.

User Sharma
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