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How long (in years) can a battery that can supply 8.30e4 J run a pocket calculator that consumes energy at the rate of 1.10e-3 W?
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How long (in years) can a battery that can supply 8.30e4 J run a pocket calculator that consumes energy at the rate of 1.10e-3 W?

User Khargoosh
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5 votes

Answer:

1 J = 1 W-sec

8.30E4 J / 1.10E-3 J/s = 7.58E7 sec

1 year = 365 d * 24 h/d * 3600 sec/hr = 3.15E7 sec

T = 7.58E7 sec / 3.15E7 sec / yr = 2.40 yrs

User Tungken
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