Question

I need help on this question I need the answer only :)

Answer 1

Step 1

Given;

Step 2

`\sqrt[3]{48y^4}=2y\sqrt[3]{6y}`
`\begin{gathered} 14(2y\sqrt[3]{6y})=28y(\sqrt[3]{6y}) \\ 17y(\sqrt[3]{6y}) \end{gathered}`

Thus;

`17y(\sqrt[3]{6y})-28y(\sqrt[3]{6y})=-11y(\sqrt[3]{6y)}`

Answer;