Question

a bit confusing to understand exactly. not so much on the math part, to get exactly what to compare.

Answer 1

77/125

Step-by-step explanation:

Probability of ordering sandwich that is either without cheese or is on sourdough bread = Probability of ordering a sandwich without cheese + probability of ordering a sourdough sandwich - probability of a sourdough sand wich without cheese

Sandwich without cheese = 425 + 700 = 1125

Sandwich with cheese = 800+ 1200 = 2000

Total of sandwich with or without cheese = 1125 + 2000 = 3125

Probability of ordering a sandwich without cheese = 1125/3125

Probability of ordering a sandwich without cheese = 9/25

ordering a sourdough sandwich = 800 + 425 = 1225

probability of ordering a sourdough sandwich = 1225/3125

probability of ordering a sourdough sandwich = 49/125

sourdough sandwich without cheese = 425

probability of a sourdough sandwich without cheese = 425/3125

probability of a sourdough sandwich without cheese = 17/125

Probability of ordering sandwich that is either without cheese or is on sourdough bread:

`\begin{gathered} =(9)/(25)+(49)/(125)-(17)/(125) \\ =\text{ }(5(9)+49-17)/(125)=(45+49-17)/(125) \\ =(77)/(125) \end{gathered}`