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Write the given statement in an equivalent exponential form.log 216 = 8V2The equivalent exponential form of the given statement is(Type your answer using exponential notation. Do not simplify.)

User Soniiic
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We can rewrite the square root as :


\sqrt[]{a}=a^{(1)/(2)}

Then:


\log _{2^{(1)/(2)^{}}}16=8

Use the next property:


\log _ax=y\text{ is equal to }a^y=x

Where a=2^(1/2), x=16 and y=8

Then:


\log _{2^{(1)/(2)^{}}}16=8\text{ is equal to (}2^{(1)/(2)})^8=16

Simplify the expression:


\text{(}2^{(1)/(2)})^8=2^4^{}

Then:


2^4=16

User Crowie
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