SOLUTION:
The vertical asymptotes are the lines x=2 or x= -2
The horizontal asymptote is when y = 0
Holes: There are no holes
Domain:
![\begin{gathered} \lbrack-\infty\text{ }<p>Range:</p>[tex]\begin{gathered} \lbrack-\infty<p></p>[tex]\begin{gathered} \frac{2}{x^2-4^{}}\text{ = }(2)/((*-2)(x+2)) \\ x\text{ - 2 = 0} \\ x\text{ =2} \\ X\text{ + 2 =0} \\ X\text{ = -2} \\ vertical\text{ }asymptotes \end{gathered}]()
For the horizontal asymptotes, since the degree of the numerator is less than that of the denominator, then y=0 is the horizontal asymptotes.