Question

In three days Carter drove 2196 miles in 36 hours behind the wheel. The first day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than on the first day, then how many hours did he drive each day? I have x=z+4 and that's all, I need the other two equations please helpp.

Answer 1

first day=10 hours, second day=12 hours, third day=14 hours

Explanation:

64+62+58=

126+58=184

o=day 1. t=day 2. th=day 3

o+t+th=36

o+4=th

64o+62t+58th=2196

(o+t+th=36)*58

58o+58t+58th=2088

64o+62t+58th=2196

-(58o+58t+58th)=2088

6o+4t=108

o+t+th=36

o+t+o+4=36 ==> th=o+4

2o+t+4=36

2o+t=32

(2o+t=32)*3

6o+4t=108

-(6o+3t=96)

t=108-96

t=12

2o+12=32 ==> 2o+t=32

2o=20

o=10

o+4=th

10+4=14

th=14

o=10, t=12, th=14