Answer:
2k(2c + 5)(k - 4)
Explanation:
Part A
4ck² + 10k² - 16ck - 40k ← factor out 2k from each term
= 2k(2ck + 5k - 8c - 20)
Part B
factor the parenthesis ( 2ck + 5k - 8c - 20 )
factor the first/second and third/fourth terms
= k(2c + 5) - 4(2c + 5) ← factor out (2c + 5) from each term
= (2c + 5)(k - 4)
then
4ck² + 10k² - 16ck - 40k = 2k(2c + 5)(k - 4)