Question

7. What is the equation of the line in slope intercept

form that passes through (6,8) and (-2,4)

Answer 1

`(\stackrel{x_1}{6}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{6}}} \implies \cfrac{ -4 }{ -8 } \implies \cfrac{ 1 }{ 2 }`

`\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{ \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{6}) \\\\\\ y-8=\cfrac{ 1 }{ 2 }x-3\implies {\Large \begin{array}{llll} y=\cfrac{ 1 }{ 2 }x+5 \end{array}}`