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Solve the radical equation AND find the extraneous solutions: √(2x + 3) = x

User Buaban
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1 Answer

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Answer:


(x+1)(x-3)=0\\x=-1,3\\√(2(-1)+3)=-1\\ √(1)=-1\\ √(2(3)+3)=3\\ √(9)=3\\

There are no extraneous solutions

Explanation:

To solve this equation, first we want to cancel out the radical;


(√(2x+3) )^2=x^2; 2x+3=x^2

Now that the equation looks simpler, we can slide 2x+3 to the other side to create a polynomial that we can factor;


x^2-2x-3=0\\(x+1)(x-3)=0

You can check for extraneous solutions by plugging the answers in, which I showed above.

User Lucas Lima
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