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Calculate the molality of a solution that contains 1.875 g of potassium chloride (KCl) in 175g water.

User Niken
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1 Answer

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Molality = moles of solute / kg of solvent

(1.875g KCl) x (1 mole KCl/74.5513 g) = 0.02515047 moles KCl

(175 g water) x (1kg/1000g) = 0.175 kg water

0.02515047 / 0.175 = 0.144 m/kg = answer
User Ranga
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