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Solve by factoring. n to the second power +2n -24 =0

Solve by factoring. n to the second power +2n -24 =0-example-1
User Stefanny
by
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1 Answer

2 votes

Explanation:

3.

the fact the three factor of n² is simply 1 tells us that the factors look like

(n + a)(n + b)

the fact that the last term is -24 (negative) tells us that one of a, b is positive and the other negative.

so, the factors are looking like

(n + a)(n - b)

and a×-b = -24.

the fact that the midterm is 2n means that a - b = 2.

so, the factors of 24 with difference of 2 are 6 and 4.

and the factoring is

(n + 6)(n - 4) = 0

the solutions to that are all values for n that make this equation true.

when is a multiplication 0 ?

when at least one factor is 0.

n + 6 = 0

n = -6

n - 4 = 0

n = 4

-6, 4 are the solutions.

that is the third answer option.

4.

-5 + 2x² = -6x

let's bring this into the firm of a regular quadratic equation :

2x² + 6x - 5 = 0

the general solution is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 2

b = 6

c = -5

and we get

x = (-6 ± sqrt(6² - 4×2×-5))/(2×2) =

= (-6 ± sqrt(36 - 4×2×-5))/4

that is the third answer option.

User Juanetta
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4.9k points