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5 votes
Write an equation for the line that is

perpendicular to the line y = 4x + 9
and goes through the point (2, 8).

User Kamoor
by
8.2k points

1 Answer

6 votes

Answer:


\sf y =(-1)/(4)x+(17)/(2)

Explanation:

Equation of the line: y =mx + b

where m is slope and b is y-intercept.

y = 4x + 9

Slope = m₁ = 4


\sf \text{Slope of the perpendicular line = $(-1)/(m_1)$}


\sf \boxed{m = (-1)/(4)}


\sf y =(-1)/(4)x +b

The point (2,8) passes through the line. Substitute in the above equation to find 'b'.


\sf 8 = (-1)/(4)*2+b\\\\\\ 8 = (-1)/(2)+b\\\\


\sf 8+(1)/(2)=b\\\\ (16)/(2)+(1)/(2)=b\\\\ \boxed{b=(17)/(2)}

Equation of the line:


\sf y =(-1)/(4)x + (17)/(2)

User Huisinro
by
8.8k points

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