Question

Math questions! Urgent help!!!

Answer 1

Question 3

d. No, because the TV is too tall

Question 4

b. 77

Explanation:

Question 3

The TV diagonal is 80"

Let W be the width of the TV, H the height

Because the aspect ratio W/H = 4/3, the height is less than the width and H = 3/4W

The diagonal of the TV can be determined by the Pythagorean formula

`D = √(W^2 + H^2)`

Express H in terms of W

`D = \sqrt{W^2 + \left((3)/(4)W\right)^2}\\\\\\= \sqrt{W^2 + (9)/(16)W^2}\\\\= \sqrt{(25)/(16)W^2}\\\\= (5)/(4)W\\\\We are given that D = 80`

The height of the available area is only 47" so the TV wont fit. The width appears OK though it will be a tight fit since width of TV and width of area are both 64"

Question 4

Note: All percentages converted to decimals first by dividing by 100

Average of 3 tests = (86 + 78 + 40)/3 = 68
Weighted average= 68 x 0.45 = 30.6

Average of 4 quizzes = (96 + 91 + 94 + 99) = 95
Weighted Average = 95 x 0.20 = 19

Classwork Average = 95
Weighted Average = 95 x 0.05 = 4.75

Final Exam = 76
Weighted value = 76 x 0.30 = 22.5

Total Weighted Score = 30.6 + 19 + 4.75 + 22.5 = 76.85 which rounded to the nearest integer is 77

Answer is b,