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Find the 8th term of the geometric sequence shown below. -2x^5, 4x^10, -8x^15

User Wwwmarty
by
8.2k points

1 Answer

5 votes

Answer:

a₈ = 256
x^(40)

Explanation:

the nth term of a geometric sequence is


a_(n) = a₁
(r)^(n-1)

where a₁ is the first term and r the common ratio

here a₁ = - 2
x^(5) and r =
(a_(2) )/(a_(1) ) =
(4x^(10) )/(-2x^(5) ) = - 2
x^(5) , then

a₈ = - 2
x^(5)
(-2x^5)^(7)

= - 2
x^(5) [
(-2)^(7) ×
x^(5(7)) ]

= - 2
x^(5) × - 128
x^(35)

= 256
x^(40)

User Nayana Adassuriya
by
7.7k points

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