Consider the following at 25°C:
1. 2ClF + O2 ----> Cl2O +F2O ΔH1 = 167.4 kJ/ mole Cl2O
2. 2ClF3 +2O2 -----> Cl2O + 3F2O ΔH2 = 341.4 kJ / mole Cl2O
3. 2F2 + O2 ---> 2F2O ΔH3 = -43.4 kJ / mole O2
At the same temperature, calculated ΔH rxn for
ClF + F2 -----> ClF3
a. -217.5 kJ/ mole
b. -130.2 kJ/mole
c. +217.5 kJ/mole
d. -108.7 kJ/mole
e. none given